((2)/(m-3))+(1/m)=((6)/(m^2-3m))

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Solution for ((2)/(m-3))+(1/m)=((6)/(m^2-3m)) equation: 


D( m )

m = 0

m-3 = 0

m^2-(3*m) = 0

m = 0

m = 0

m-3 = 0

m-3 = 0

m-3 = 0 // + 3

m = 3

m^2-(3*m) = 0

m^2-(3*m) = 0

m^2-3*m = 0

m^2-3*m = 0

DELTA = (-3)^2-(0*1*4)

DELTA = 9

DELTA > 0

m = (9^(1/2)+3)/(1*2) or m = (3-9^(1/2))/(1*2)

m = 3 or m = 0

m in (-oo:0) U (0:3) U (3:+oo)

2/(m-3)+1/m = 6/(m^2-(3*m)) // - 6/(m^2-(3*m))

2/(m-3)-(6/(m^2-(3*m)))+1/m = 0

2/(m-3)-6*(m^2-3*m)^-1+1/m = 0

2/(m-3)-6/(m^2-3*m)+1/m = 0

m^2-3*m = 0

m^2-3*m = 0

m*(m-3) = 0

m-3 = 0 // + 3

m = 3

m*(m-3) = 0

2/(m-3)-6/(m*(m-3))+1/m = 0

(2*m)/(m*(m-3))-6/(m*(m-3))+(1*(m-3))/(m*(m-3)) = 0

1*(m-3)+2*m-6 = 0

2*m+m-6-3 = 0

3*m-9 = 0

(3*m-9)/(m*(m-3)) = 0

(3*m-9)/(m*(m-3)) = 0 // * m*(m-3)

3*m-9 = 0

3*m-9 = 0 // + 9

3*m = 9 // : 3

m = 9/3

m = 3

m in { 3} 

m belongs to the empty set

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